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NE555仿真
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lifeiao1 7 years ago
是从Spice库中取得555封装,但是不能仿真。![enter image description here][1] [1]: /editor/20171222/5a3ca576e4fdd.png
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andyfierman 6 years ago
如果没有看到你的项目,就不可能说出你的模拟有什么问题。你的项目是私人的,所以只有你可以看到它。为了得到这个帮助,请把你的项目公开。在此之前,请尝试阅读(3):https://easyeda.com/andyfierman/Welcome_to_EasyEDA-31e1288f882e49e582699b8eb7fe9b1f(Google或Bing翻译应该没问题)。 Without sight of your project, it is not possible to say exactly what might be wrong with your simulation.Your project is private so only you can see it. For help on this, please make your project public. Until then, please try to read (3) in: https://easyeda.com/andyfierman/Welcome_to_EasyEDA-31e1288f882e49e582699b8eb7fe9b1f (Google or Bing translate should be ok).
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andyfierman 6 years ago
对不起,我的错误(我用我的手机来翻译,没有显示你的电路图的截图)。 您需要使12V电源(V1)从0V到12V产生一个阶跃,以启动555电路。 在** V1 **中替换 `12` 有: `PULSE(0 12)` 或者添加一个spice指令: `.ic V(volprobe2)= 0` (添加文本,然后设`文字类型= spice1`) Sorry, my mistake (I used my phone to translate and it did not show me the screenshot of your schematic). You need to make the 12V supply (V1) produce a step from 0V to 12V to start up the 555 circuit. In **V1** replace `12` with: `PULSE(0 12)` or add a spice directive: `.ic V(volprobe2)=0` (add text then set `text type=spice1`)
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lifeiao1 6 years ago
@andyfierman 谢谢您,我的问题解决了。
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